1.2+16.5x+4.905x^2=0

Solution for 1.2+16.5x+4.905x^2=0 equation:

1.2+16.5x+4.905x^2=0

a = 4.905; b = 16.5; c = +1.2;
Δ = b2-4ac
Δ = 16.52-4·4.905·1.2
Δ = 248.706
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16.5)-\sqrt{248.706}}{2*4.905}=\frac{-16.5-\sqrt{248.706}}{9.81}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16.5)+\sqrt{248.706}}{2*4.905}=\frac{-16.5+\sqrt{248.706}}{9.81}
$